By simply using this binomial coefficient one can compute the numbers of possible combinations (for numbers until 10, see Table 3 leftmost numbers in cells) which gives the inner portion of Pascal’s triangle. However, the outer 1s are missing, since the extension itself is no abbreviation and neither is a sequence of zero letters, the sum is thus 2^w - 2. The increase in possibilities is linear and quick, for a word of length 15, there are 32,766 possibilities how it could be abbreviated.